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Linear Algebra Chapter 5: Eigenvalues, Eigenvectors, and Diagonalization

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Eigenvector#

線性運算的特徵向量 / eigenvalue of a linear operation

T(v)=λvT(\mathbf{v}) = \lambda \mathbf{v}

矩陣的特徵向量 / eigenvalue of a matrix

Av=λvA\mathbf{v} = \lambda \mathbf{v}

Eigenvalue#

The characteristic polynomial is defined as below.

  • f(t)=antn+an1tn1++a1t+a0Inf(t) = a_n t^n + a_{n-1}t^{n-1} + \dots + a_1t + a_0 I_n
  • f(t)=det(AtIn)f(t) = \det(A-tI_{n})

Eigenvalues must satisfy the following equation of tt (characteristic equation):

f(t)=0f(t) = 0

Multiplicity#

Multiplicity of λ\lambda: the maximum kk for the term (tλ)k(t-\lambda)^{k} in the characteristic polynomial.

Theorem. The dimension of the eigenspace must not be greater than its multiplicity.

Diagonalizable#

A matrix AA is called diagonalizable if there exists

  • a diagonal matrix DD
  • an invertible PP such that
A=PDP1.A = PDP^{-1}.

Corollary.

Am=PDmP1.A^{m} = PD^{m}P^{-1}.

Propositions about Diagonalization#

  • The set of column vectors of PP is a basis of Rn\mathbb{R}^{n}.
  • The set of column vectors of PP consists of eigenvectors of AA.
  • Entries of DD consists of eigenvalues corresponding to column vectors of PP.

Theorem. For any two eigenvectors, if their corresponding eigenvalues are distinct, they are linearly independent.

Diagonalizability#

  1. The number of eigenvalues, taking multiplicity into consideration, is equal to the dimension.
  2. Dimension of eigenspace = multiplicity

Theorem.

  • Linear operation TT is diagonalizable if and only if
  • there exists a basis B\mathcal{B} such that [T]B[T]_{\mathcal{B}} is diagonal.

Note: [T]B=B1AB[T]_{\mathcal{B}}=B^{-1}AB.

Linear Algebra Chapter 5: Eigenvalues, Eigenvectors, and Diagonalization
https://blade520.com/posts/linear-algebra/ch5/
作者
Blade/磯江
發佈於
2025-12-03
許可協議
CC BY-NC-SA 4.0